FERTILIZER CHHIARKAWP

 Mizoram loneitu leh huan neituten thlai chawm nana leitha hman a hlawkzia kan hmufuh ve tan ta a. Khawpui chhung leh a chhehvel khuaa hnephnawl chingtute phei chuan leitha hman an uar ta hle. Hei hian hma kan sawn tak zia a tilang chiangin Agriculture mite beiseina pawh a tisei hle. Amaherawhchu, kan leitha hman danah hian kan la arkhawthimdai hle thova, tisual nasa ngiang lah kan awm reng bawk. A thu hrimah thlai hrang hrang tana leitha pek zat tur kan sawi hian Nitrogen, Phosphorus leh Potassium lamin kan sawi a, kan pek tak erawhchu leitha (Fertilizer) te a ni leh daih lawi si a. Leitha chi hrang hrang an chaw pai leh an pai zat pawh inanglo thlih thliah hlawm si hi thlaiin an mamawh zah chawhchhuah saka dik taka pek a ngai a. Chutianga kan chawhchhuah thiam theih nan mawl tein a chawhdan ka han buatsaih a. Hei hi thlai chingtu leh Extension hnathawk mekte tan tanpuitu tha tak a nih ka beisei.


Table 38 : FERTILIZER LEH AN CHAWPAI ZAT


Sl.No.
 Fertilizer hming
An chawpai zat, za zelah (%)
N
P2O2
K2O
A
 Nitrogen pai fertilizer-te
1
 Ammonium Sulphate
20
-
-
2
 Ammonium Nitrate
32-35
-
-
3
 Sodium Nitrate
16
-
-
4
 Ammonium Sulphate Nitrate
26.5
-
-
5
 Ammonium Chloride
25-26
-
-
6
 Cal. Ammonium Nitrate Gr.I
20
-
-
7
 Cal. Ammonium Nitrate Gr.II
26
-
-
8
 Calcium Cyanide
15-18
-
-
9
 Anhydrous Ammonia
15
-
-
10
 Urea
46
-
-
B
 Phosphorus pai fertilizer-te
1
 Single superphosphate (SSP)
-
16
-
2
 Double superphosphate (DSP)
-
32-40
-
3
 Triple superphosphate (TSP)
-
45-48
-
4
 Bonemeal
-
20-25
-
5
 Bonemeal steamed
-
25-30
-
6
 Rock Phosphate
-
25-35
-
7
 Dicalcium Phosphate
-
34
-
8
 Bone ash
-
35
-
C
 Potassium pai fertilizer
-
1
 Muriate of Potash (MOP)
-
60
2
 Potassium Sulphate
-
-
-
D
 Chawhpawlh fertilizer
1
 Ammonium Sulphate Phosphate
16
20
-
2
 Manure Ammonium Phosphate
11
48
-
3
 Diammonium Phosphate (DAP)
18
64
-
4
 Ammonium Super Phosphate
4-7
14-20
-
5
 Ammonium Nitrate Phosphate
32-35
-
-
6
 Nitro Phosphate
12.9
12.9
-
7
 Ammonium Phosphate A
11
45-48
-
8
 Ammonium Phosphate B
16
20
-
9
 Grow more
20
20
-
10
 Potassium Nitrate
13
-
44
11
 Nitro Phoska
13
13.5
21
12
 Suphla
15
15
15
13
 NPK No. 2
15
15
15

HNIMHNAH TAWIH LEH RAN ZUN-EK LEITHA CHAW PAI ZAT


Sl.No.
 LeiTha hming
An chawpai zat, za zelah (%)
N
P2O2
K2O
A
 FRAM ATANGA LEITHA
1
 Compost (Thingtlang)
1.0
0.4-0.8
0.8-1.2
2
 Compost (Khawpui)
0.7-2.0
0.9-3.0
1.0-2.0
3
 F.Y.M.
0.4-1.5
0.3-0.9
0.3-1.9
4
 RAN ZUN-EK CHAWPAI ZAT
1
 Bawngek
0.3-0.4
0.1-0.2
0.1-0.2
2
 Horse (Sakawrek)
0.4-0.5
0.3-0.5
0.3-0.8
3
 Beram leh Kelek
0.6
0.8
0.7
4
 Ar ek
1.4
1.6
0.8
5
 Thli/Tuichhia
0.5
0.5
0.4
6
 Bawng zun
1.1
-
1.4
7
 Sakawr zun
1.3
-
-
8
 Beram leh Kel zun
1.6
-
-

LEITHA PEK ZAH TUR CHHUTCHHUAH DAN

 Fertilizer pek zat tur chhutchhuak turin Rule of Three dan hmanga kan hriat duh dah hnuhnun thin tur a ni.

 1. Buh hmun hectare 1 a zauvah Urea hmangin Nitrogen kg 100 i pe dawn a, Urea kg engzahnge pek ngai ang ?

  Urea kg 100 a kg 46 hi Nitrogen a ni.

  N kg 46 hi Urea      kg 100 in a pai a,


  N kg 1 pai chu a tlem  100 ∕ 46 ( Kan sem ang)


  N kg 100 pai chin atam (100 ×100) ∕ 46 (Kan puntir ang) = Kg 217.39


    Urea pek ngai zat = Kg 217.39


  2. Pa pakhatin a fu huan hectare khata zauah Nitrogen kg 240 hisapin pek a duh a, hectare 2 a zau, fu huan chawm nan Amm. Sulphate leh Urea hmang se engzatnge pek ngai ang ?


 Amm. Sulphate kg 100 a kg 20 hi Nitrogen a ni,


 Urea kg 100 a kg 46 pawh hi Nitrogen a ni.

 Nitrogen pek ngai zat  =  Hectare 1 ah kg 240

              =  Hectare 2 ah kg 480

 Amm. Sulphate hmanga pek tur zat  =  kg 240

 Urea hmanga pek tur zat pawh    =  kg 240


Step 1 na :

Therefore,  N kg 20 hi Amm. Sulphate kg 100 in a pe thei a,

        N kg 1 hi Amm. Sulphate kg 100 ∕ 20 in a pe thei a,

        N kg 240 hi Amm. Sulphate kg (100×240) ∕ 20  =   (Kg 240 pe tur a tam avangin kan puntir)

      =  Amm. Sulphate kg 1200


Step 2 na :

Therefore, N kg 46 hi Urea kg 100 in a pe thei a,

        N kg 1 hi Urea kg 100 ∕ 46

        N kg 240 hi Urea kg (100 × 240) ∕ 46  =  Urea kg 521.73

Leitha pek tur zat :

Amm. Sulphate kg 1200.00

Urea        kg 521.73


 3.  Fu huan hectare khata zau chawm nan Nitrogen kg 135, P2O5 kg 70 leh Potassium kg 60 Amm. Sulphate, Single Superphosphate (SSP) leh Potassium Sulphate leithate hmangin pe dawn la, heng leithate hi engzah theuh nge pek ngai ang ?


Amm. Sulphate kg 100 a kg 20 hi Nitrogen a ni,

SSP kg 100 a kg 16 hi Phosphorus a ni,

Potassium Phosphate kg 100 a kg 50 hi Potassium a ni.


Step 1 na :

Therefore, N kg 20 hi Amm. Sulphate kg 100 in a pe thei.

        N kg 1 hi Amm. Sulphate kg 100 ∕ 20 in a pe thei.

        N kg 135 hi Amm. Sulphate kg (100 ×135)  ∕ 20  = Amm. Sulphate kg 675

Step 2 na :


Thererfore, P2O5 kg 16 hi SSP kg 100 in a pe thei.

        P2O5 kg 1 hi SSP kg 100 ∕  16

        P2O5 kg 135 hi SSP kg (100 × 70) ∕  16 = SSP kg 437.50

Step 3 na :

Therefore, K2O kg 50 hi Potassium Sulphate kg 100 in a pe thei.

       K2O kg 1 hi Potassium Sulphate kg 100 ∕ 50

       K2O kg 60 hi Potassium Sulphate kg (100 × 60) ∕ 50 = Potassium Sulphate kg 120


Leitha pek tur zat chu :

Amm. Sulphate      kg 675.00

SSP             kg 437.50

Potassium Sulphate    kg 120.00

 Ammonium Sulphate aia Urea kan hman duh zawk emaw Potassium Sulphate aia Muriate of Potash kan hman duh zawk emaw chuan ti hian a chhut theih ang. Urea kg 100 in Nitrogen kg 40 a pe thei a,

MOP kg 100 pawhin Potassium kg 60 a pe thei


Step 1 na :

Therefore, N kg 46 hi Urea    kg 100 in a pe thei

       N kg 1 hi Urea      kg 100  ∕ 46

       N kg 135 hi Urea     kg (100 ×  135) ∕ 46 = Urea kg 293.50


Step 2 na :

Therefore, K2O kg 50 hi MOP     kg 100 in a pe thei

       K2O kg 1 hi MOP       kg 100 ∕ 50

       K2O kg 60 hi MOP     kg (100 ×60) ∕ 50 = MOP Kg 120


Leitha pek tur zat chu :

 Urea    kg 293.50

 SSP     kg 437.50

 MOP    kg 120.00


 4. Loneitu pakhatin a thlai chawm nan N kg 150, P2O5 kg 80 pek a duh a, chumi pe tur chuan Calcium Ammonium Nitrate I (CAN I), Triple Superphosphate (TSP) leh Muriate of Potash (MOP) te hmang dawn se, engzat theuh nge pek tul ang ?

CAN I kg 100 in Nitrogen kg 20 a pai a,

TSP kg 100 in Phosphorus kg 45-48

MOP kg 100 in Potassium kg 60 a pai bawk


Step 1 na :

Therefore, N kg 20 hi CAN I kg 100 in a pe thei

       N kg 1 hi CAN I kg 100  ∕  20

       N kg 150 hi CAN I kg (100 × 150) ∕   20 = = CAN I kg 750


Step 2 na :

Therefore, P2O5 kg 45 hi TSP kg 100 in a pe thei

       P2O5 kg 1 hi TSP kg 100 ∕ 45

       P2O5 kg 80 hi TSP kg (100 × 80) ∕ 45


Step 3 na :

Therefore,  K2O kg 60 hi MOP kg 100 in a pe thei

        K2O kg 1 hi MOP kg 100 ∕ 60 in a pe thei

        K2O kg 100 hi MOP kg (100 ×100) ∕ 60 = MOP kg 166.66


Leitha pek tur zat chu :

CAN I     kg 750.00

TSP       kg 177.77

MOP      kg 166.66


 5. Buh hmun hectare 1 a zauvah N kg 120, P2O5 kg 80 leh K2O kg 60 te hi Ammonium Nitrate (32% N) Double Superphosphate (DSP) (32% P2O5 leh Potassium Sulphate(50% K2O) leitha te hmangin pe dawn ila, engzah theuh nge kan pek ang ?


Step 1 na :

Therefore, N kg 32 hi Amm. Nitrate kg 100 in a pe thei

       N kg 1 hi Amm. Nitrate kg 100 ∕ 32 in a pe thei

       N kg 120 hi Amm. Nitrate kg (100 × 120) ∕ 32 = Amm. Nitrate kg 375


Step 2 na :

Therefore, P2O5 kg 32 hi DSP kg 100 in a pe thei

       P2O5 kg 1 hi DSP kg 100 ∕ 32

       P2O5 kg 80 hi DSP kg (100 × 80) ∕ 32 = DSP kg 250


Step 3 na :

Therefore, K 2O kg 50 hi Potassium Sulphate kg 100 in a pe thei

        K 2O kg 1 hi Potassium Sulphate kg 100 ∕ 50

        K 2O kg 60 hi Potassium Sulphate kg (100 × 60 ) ∕ 50 = Potassium Sulphate kg 120

Leitha pek tur zat chu :

Amm. Nitrate      kg 375

DSP            kg 250

Potassium Sulphate   kg 120

Source : Lalthanzuala
MSc.(Ag) ,Agro, PG Dip.Agmark
Thlai chin dan
Department of Agriculture (Crop Husbandry)
Mizoram
Page No : 183- 200
First Edition-2011


6.  N kg 75, P2O5 kg 50 leh K2O kg 25 thlai chawm nana hmang turin Amm. Sulphate, Rock Phosphate leh Muriate of Potash (MOP) leithate hman tur a ni a, kg engzah theuh nge pek tur chhut chhuak teh ?


Amm. Sulphate kg 100 a kg 20 hi Nitrogen a ni a,

Rock Phosphate kg 100 a kg 25 hi Phosphorus

MOP kg 100 a kg 60 hi Potassium


Step 1 na :

Therefore, N kg 20 hi Amm. Sulphate kg 100 in a pe thei

        N kg 1 hi Amm. Sulphate kg 100 ∕ 20

        N kg 75 hi Amm. Sulphate kg (100 ∕ 75) × 20 = Amm. Sulphate kg 375


Step 2 na :

Therefore, P2O5 kg 25 hi Rock Phosphate kg 100 in a pe thei

        P2O5 kg 1 hi Rock Phosphate kg 100 ∕ 25

        P2O5 kg 50 hi Rock Phosphate kg (100 × 50) ∕ 25 = Rock Phosphate kg 200


Step 3 na :

Therefore, K2O kg 60 hi MOP kg 100 in a pe thei

        K2O kg 1 hi MOP kg 100 ∕ 60

        K2O kg 25 hi MOP kg (100 × 25) ∕ 60 = MOP kg 41.66


Leitha pek tur zat chu :

Amm. Sulphate      kg 375.00

Rock Phosphate    kg 200.00

MOP         kg 41.66


 7.  Huan neitu pakhatin Urea, Diammonium Phosphate (DAP) leh Potassium Sulphate leithate hmangin a thlai N kg 150, P2O5 kg 80 leh K2O kg 60 a chawm a duh a. A leitha pek tur zat chawhchhuak sak teh ?


Urea kg 100 in Nitrogen kg 46 a pai a,

DAP kg 100 in Nitrogen kg 18 leh Phosphorus kg 46

Potassium Sulphate kg 100 in Potassium kg 50 a pai bawk a.


Step 1 na :

Therefore, P2O5 kg 46 hi DAP kg 100 in a pe thei a

       P2O5 kg 1 hi DAP kg 100 ∕ 46

       P2O5 kg 80 hi DAP kg (100 × 80 ) ∕ 46 = DAP kg 174


Step 2 na :

Therefore, DAP kg 100 in N kg 18 in a pe thei bawk

        DAP kg 1 in N kg 18 ∕ 100

        DAP kg 174 in N kg (18 × 174) ∕ 100 = Nitrogen kg 31.32, DAP kg 174 in a pai.


Step 3 na :

 Nitrogen pek tur zawng zawng kg 150 atangin DAP pek theih zat kg 31.32 hi kan paih anga, a la chuang chu Urea in a tum theih zah tur hmuh chhuah nan kan hmang ang.

N kg 150-31.32=kg 118.68


Step 4 na :

Therefore, N kg 46 hi Urea kg 100 in a pe thei

       N kg 1 hi Urea kg 100 ∕ 46

       N kg 118.68 hi Urea kg (100 × 118.68 ∕ 46 = Urea kg 258


Step 5 na :

Therefore, K 2 O kg 50 hi Potassium Sulphate kg 100 in a pe thei

       K 2 O kg 1 hi Potassium Sulphate kg 100 ∕ 50

       K 2 O kg 60 hi Potassium Sulphate kg (100 × 60) ∕ 50 = Potassium Sulphate kg 120


Leitha pek tur zat chu :

DAP            kg 174

Urea              kg 258

Potassium Sulphate     kg 120


 8. Nitrogen kg 100, Phosphorus kg 75 leh Potassium kg 30 thlaia pe turin Amm. Sulphate, Diammomium Phosphate (DAP) leh Muriate of Potash (MOP) engzah theuh nge kan pek ngai ang ?


Step 1 na :

Therefore, P2O5 kg 46 hi DAP kg 100 in a pe thei a

       P2O5 kg 1 hi DAP kg 100 ∕ 46

       P2O5 kg 75 hi DAP kg (100 × 75 ) ∕ 46 = DAP kg 163


Step 2 na :

Therefore, DAP kg 100 in N kg 18 a pe thei bawk

       DAP kg 1 in N kg 18 ∕ 100

       DAP kg 163 in N kg ( 18 × 163) ∕ 100 = Nitrogen kg 29.34


Step 3 na :

 Nitrogen pek tur zawng zawng kg 100 atangin DAP pek theih zat kg 29.34 hi kan paih anga, chu chu Amm. Sulphate in a tum theih zah tur hmuh chhuah nan kan hmang ang.

N kg 100-29.34=kg 70.66


Step 4 na :

Therefore, N kg 20 hi Amm. Sulphate kg 100 in a pe thei a,

        N kg 1 hi Amm. Sulphate kg 100 ∕ 20

        N kg 70.66 hi Amm. Sulphate kg (100 × 70.66) ∕ 20 = Amm. Sulphate kg 353.30


Step 5 na :

Therefore, K2 O kg 60 hi MOP kg 100 in a pe thei a,

       K2 O kg 1 hi MOP kg 100 ∕ 60

       K2 O kg 30 hi MOP kg (100 × 30) ∕ 60 = MOP kg 50


Leitha pek tur zat chu :

Amm. Sulphate    kg 353.30

DAP           kg 163.00

MOP          kg 50.00


 9. Nitrogen kg 250, Phosphorus kg 180 leh Potassium kg 100 i thlaia pe turin Urea, DAP leh MOP leithate hmang ta la, engzah theuh nge i mamawh ang ?

Urea kg 100 in Nitrogen kg 46 a pai a,

DAP kg 100 in Nitrogen kg 18 leh Phosphorus kg 46,

MOP kg 100 in Potassium kg 60 a pai bawk a.


Step 1 na :

Therefore, P2O5 kg 46 hi DAP kg 100 in a pe thei a

        P2O5 kg 1 hi DAP kg 100 ∕ 46

        P2O5 kg 180 hi DAP kg (100 × 180) ∕ 46 = DAP kg 391.30


Step 2 na :

Therefore, DAP kg 100 in N kg 18 in a pe thei bawk

        DAP kg 1 in N kg 18 ∕ 100

        DAP kg 391.30 in N kg (18 × 391.30 ) ∕ 100 = Nitrogen kg 70.43


Step 3 na :

 Nitrogen pek tur zawng zawng kg 250 atangin DAP in a pek tur zat kg 70.43 hi kan paih anga, chu chu Urea in a tum ve theih zat tur chhut chhuah nan kan hmang ang.


N kg 250.00-70.43=kg 179.57


Step 4 na :

Therefore, N kg 46 hi Urea kg 100 in a pe thei,

        N kg 1 hi Urea kg 100 ∕ 46

        N kg 179.57 hi Urea kg (100 × 179.57 ) ∕ 46 = Urea kg 390.36


Step 5 na :

Therefore, K2O kg 60 hi MOP kg 100 in a pe thei

        K2O kg 1 hi MOP kg 100 ∕ 60

        K2O kg 100 hi MOP kg (100 × 100 )∕ 60 = MOP kg 166.66


Leitha pek tur zat chu :

Urea      kg 390.36

DAP      kg 391.30

MOP      kg 166.66


 10. N kg 250, Phosphorus kg 150 leh Potassium kg 100 a buh hmun chawm turin heng DAP, Urea leh Potassium Sulphate leithate hi engzat theuh nge pek ngai ang ?


Urea kg 100 in Nitrogen kg 46 a pai a,

DAP kg 100 pawhin Nitrogen kg 18 leh Phosphorus kg 46

Potassium Sulphate kg 100 in Potassium kg 50 a pai bawk.


Step 1 na :

 DAP hian Nitrogen leh Phosphorus a pai kawp avangin Phosphorus kg 150 hi DAP hmangin kan pe mai ang.

Therefore, P2O5 kg 46 hi DAP kg 100 in a pe thei a

        P2O5 kg 1 hi DAP kg 100 ∕ 46

        P2O5 kg 150 hi DAP kg (100 × 150) ∕ 46 = DAP kg 326


Step 2 na :

 DAP hian Nitrogen a pai tel avangin Nitrogen pek tur kg 250 ah hian engemawzat chu DAP kan tumtir nghal ang.

Therefore, DAP kg 100 in N kg 18 in a pe thei bawk

       DAP kg 1 in N kg 18 ∕ 100

       DAP kg 326 in N kg (18 × 326 ) ∕ 100 = Nitrogen kg 58.68


Step 3 na :

 Nitrogen pek tur zawng zawng kg 250 atangin DAP in a pek tur zat kg 58.68 hi kan paih anga, chu chu Urea in a tum ve theih zat tur chhut chhuah nan kan hmang ang.

N kg 250.00-58.68 = kg 191.32


Step 4 na :

Therefore, N kg 46 hi Urea kg 100 in a pe thei,

       N kg 1 hi Urea kg 100 ∕ 46

       N kg 191.32 hi Urea kg (100 × 191.32 ) ∕ 46 = Urea kg 415.91


Step 5 na :

Therefore, K2O kg 50 hi Potassium Sulphate kg 100 in a pe thei,

K2O kg 1 hi Potassium Sulphate kg 100 ∕ 50

K2O kg 100 hi Potassium Sulphate kg (100 × 100) ∕ 50 = Potassium Sulphate= kg 200


Leitha pek tur zat chu :

DAP            kg 326.00

Urea            kg 415.91

Potassium Sulphate      kg 200.00


 11. Wheat chawm nan Nitrogen kg 120, Phosphorus kg 80 leh Potassium kg 60 pek a tul a, Amm. Sulphate, Single Superphosphate (SSP) leh Muriate of Potash (MOP) leitha hmanga pek tur ni ta se, engzat theuh nge ngai ang chhut chhuak teh ?

Amm. Sulphate kg 100 in Nitrogen kg 20 a pe thei a,

SSP kg 100 pawhin Phosphorus kg 16 a pe thei a,

MOP kg 100 in Potassium kg 60 a pe thei bawk.


Step 1 na :

Therefore, N kg 20 hi Amm. Sulphate kg 100 in a pe thei,

       N kg 1 hi Amm. Sulphate kg 100 ∕ 20

       N kg 120 hi Amm. Sulphate kg (100 ×120) ∕ 20 Amm. Sulphate kg 600


Step 2 na :

Therefore, P2O 5 kg 16 hi SSP kg 100 in a pe thei a

       P2O 5 kg 1 hi SSP kg 100 ∕ 16

       P2O 5 kg 80 hi SSP kg (100 &x215; 80 ) ∕ 16 = SSP kg 500


Step 3 na :

Therefore, K2O kg 60 hi MOP kg 100 in a pe thei,

        K2O kg 1 hi MOP kg 100 ∕ 60

        K2O kg 60 hi MOP kg (100 × 60) ∕ 60 = MOP= kg 100


Leitha pek tur zat chu :

Amm. Sulphate     kg 600

SSP          kg 500

MOP           kg 100


 12. Sugarbeet hectare 1 hmun Nitrogen kg 240, Phosphorus kg 120 leh Potassium kg 80 a chawm turin Amm. Sulphate, Doble Superphosphate (DSP) leh Muriate of Potash (MOP) leithate hmang la, engzah theuh nge ngai ang ?


Amm. Sulphate kg 100 in Nitrogen kg 20 a pe thei a,

Double Superphosphate kg 100 in Phosphorus kg 32-40 a pe thei,

MOP kg 100 pawhin Potassium kg 60 a pe thei.


Step 1 na :


Therefore, N kg 20 hi Amm. Sulphate kg 100 in a pe thei,

       N kg 1 hi Amm. Sulphate kg 100 ∕ 20

       N kg 240 hi Amm. Sulphate kg (100 × 240) ∕ 20 = Amm. Sulphate kg 1200


Step 2 na :

Therefore, P2O5 kg 40 hi DSP kg 100 in a pe thei

       P2O5 kg 1 hi DSP kg 100 ∕ 40

       P2O5 kg 120 hi DSP kg (100 × 120) ∕ 40 = DSP kg 300


Step 3 na :

Therefore, K2O kg 60 hi MOP kg 100 in a pe thei,

        K2O kg 1 hi MOP kg 100 ∕ 60

        K2O kg 80 hi MOP kg (100 × 80) ∕ 60 = MOP= kg 133.33


Leitha pek tur zat chu :

Amm. Sulphate      kg 1200.00

DSP          kg 300.00

MOP          kg 133.33


 13. Loneitu pakhatin a buh hmun N kg 150, P2O5 kg 125 leh K2O kg 60 a chawm turin Urea, DAP leh Potassium Sulphate te hmang ta se engzah theuh nge a mamawh ang ?


Urea kg 100 in Nitrogen kg 46 a pe thei a,

DAP kg 100 in Nitrogen kg 18 leh Phosphorus kg 46

Potassium Sulphate kg 100 in Potassium kg 50 a pe thei bawk.


Step 1 na :

Therefore, P2O 5 kg 46 hi DAP kg 100 in a pe thei

       P2O 5 kg 1 hi DAP kg 100 ∕ 46

       P2O 5 kg 125 hi DAP kg (100 × 125 ) ∕46 = = DAP kg 271.73


Step 2 na :

Therefore, DAP kg 100 in N kg 18 a pe thei bawk

       DAP kg 1 in N kg 18 ∕ 100

       DAP kg 271.73 in N kg 18 × 271.73 ∕ 100 = Nitrogen kg 49


Step 3 na :

  Nitrogen pek tur zawng zawng kg 150 atangin DAP in a tum theih zat kg 49 kan paih anga, a la chuang kg 101 hi Urea in a tum ve tur chhut chhuah nan kan hmang ang.


Step 4 na :

Therefore, N kg 46 hi Urea kg 100 in a pe thei,

       N kg 1 hi Urea kg 100 ∕ 46

       N kg 101 hi Urea kg (100 × 101) ∕ 46 = Urea kg 219.56


Step 5 na :

Therefore, K2O kg 50 hi Potassium Sulphate kg 100 in a pe thei,

        K2O kg 1 hi Potassium Sulphate kg 100 ∕ 50

       K2O kg 50 hi Potassium Sulphate kg (100 × 60) ∕ 50 Potassium Sulphate kg 120.00


Leitha pek tur zat chu :

Urea            kg 219.56

DAP            kg 271.73

Potassium Sulphate      kg 120.00

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